SOLUTION TO PROBLEM R-2

If t is even, after t² minutes all the lattice points of the $t\times t$ square

$$\{(x,y):0\leq x \leq t-1\ \&\ 0\leq y\leq t-1\}$$

have been visited, and the particle is at (0,t). Now, 2002=44²+66, and 66=44+22. After 44² minutes the particle is at (0,44), 44 minutes later its location is (44,44), and 22 minutes after that it is at (44,22).

Questions and/or comments should be directed to Judy Downey or Griff Elder

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Last modified:   Sat Jan 26 12:38:12 CST 2002