SOLUTION TO PROBLEM 1:

We know that 60^b=5, and hence

$$60^{1-b}=\frac{60}{60^b}=\frac{60}{5}=12.$$

Therefore

$$12^{\frac{1-a-b}{2(1-b)}}=(60^{1-b})^{\frac{1-a-b}{2(1-b)}}= ... ...=\sqrt{\frac{60}{60^a\cdot 60^b}}=\sqrt{\frac{60}{3\cdot 5}}=2.$$

Questions and/or comments should be directed to Judy Downey or Griff Elder

    BACK
 
 

Last modified:   Fri Sep 1 14:23:18 CDT 2000