Solution to Problem 8



By the Remainder Theorem, we have p(a)=a, p(b)=b, p(c)=c. Assuming that a,b,c are distinct, we can write

p(x)=(x-a)(x-b)(x-c)q(x)+r(x),

where r(x) is a polynomial of degree at most 2. We must have r(a)=a, r(b)=b, r(c)=c. Hence the polynomial r(x)-x has degree at most 2 and roots a,b,c, and must therefore be the zero polynomial. Thus, x is the remainder.



Questions and/or comments should be directed to Judy Downey or Griff Elder


[Back]    BACK
 
 


Last modified:   Wed Oct 18 09:12:11 CDT 2000